In this article we are going to implement the program that is find the three biggest   element in the array   To solve this problem we are actually going to use C ++  Programming language.


In this article we are discussed  about the below points


  • Question
  • Logic
  • Source code
  • Using function solve
  • Feedback


Question-

Write a program in c language to find out the three biggest element in the array.




Logic

  • Take an array of some integers then take a variable ( n )  for taking the input how many data the user want to enter then run a for loop to taking the inputs . 
  • Again run another for loop and inside the loop use if condition for checking the large elements in the array , Take a variable for comparing the large element,.
  • Then check inside the if the condition that the value that is larger than that assign it to large and print the large value
  • Then again run a for loop to and this time run till 3 times ( i !=3) and print the array




Source code


USING FOR LOOP


#include <iostream>

using namespace std;

int main()

{

    int n,first,second,third;

    //Initialize the largest three elements as zero

    third = first = second = 0;

    cout << "Enter the size :" << endl;

    cin >> n;

    int arr[100];

    for (int i = 0; i < n; i++)

    {

        cout << "Enter the element no." << i + 1 << " :";

        cin >> arr[i];

    }

    for (int i = 0; i < n; i++)

    {

        if (arr[i] > first)

        {

            third = second;

            second = first;

            first = arr[i];

        }

        else if (arr[i] > second)

        {

            third = second;

            second = arr[i];

        }

        else if (arr[i] > third)

        {

            third = arr[i];

        }

    }

    cout << "The large 3 elements are :\n";

        cout << first << endl

             << second << endl

             << third;


    return 0;

}





USING FUNCTION



#include <iostream>

using namespace std;

void threelarge(int arr[], int n)

{

    int first, second, third;

    //Initialize the largest three elements as zero

    third = first = second = 0;

    for (int i = 0; i < n; i++)

    {

        if (arr[i] > first)

        {

            third = second;

            second = first;

            first = arr[i];

        }

        else if (arr[i] > second)

        {

            third = second;

            second = arr[i];

        }

        else if (arr[i] > third)

        {

            third = arr[i];

        }

    }

    cout << "The large 3 elements are :\n";

        cout << first << endl

             << second << endl

             << third;

}

    int main()

    {

        int n;

        cout << "Enter the size :" << endl;

        cin >> n;

        int arr[100];

        for (int i = 0; i < n; i++)

        {

            cout << "Enter the element no." << i + 1 << " :";

            cin >> arr[i];

        }

        threelarge(arr, n);

    }

    




As we already discussed about the program logic hopefully you can understand the program now and still any doubts please comment below we will try to reach out you soon

Thank you.



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FEEDBACK 

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