What you learn from the problem

  • This solution will help you To learn how to use Conditional Statements in C++.

  • if else and if else-if are the two of the most used conditions in c and c++,this two conditional statements are mostly used in c and c++.

   Conditional Statements in C++

 SYNTAX


     if conditional statement


    if(condition)
   {
    statement1;
    }

  • if the condition becomes true the statement will true ,if the condition become false program will terminates.



if -else conditional statement


if(condition)
{
  statement1;
}
else
{
 statement2;
}


if the condition becomes true the 1st statement will true else the statement2 will true



 

if -else-if else conditional statement


  • if - else if - else: In this structure, dependent statements are chained together and the  for each statement is only checked if all prior conditions in the chain evaluated to false. 

  • Once a  evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing.

  •  If each  in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.


if(condition)
{
   .....
}
else if (second condition)
{
 ..........
}
else if (statement ...)
{
  ......
}
else
{
}


Input Format


A single integer, n

Constraints

Output Format


If   , ,, then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9.


Sample input


5

Sample Output 0


five

Explanation 0

five is the English word for the number .

Sample Input 1

8

Sample Output 1

eight

Explanation 1

eight is the English word for the number .

Sample Input 2


44

Sample Output 2


Greater than 9

Disclaimer :-

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Explanation about problem

  • --->  first of all you have to take inputs from the
  • ---> keyboard if the number entered is between
  • ---> 1 to 9 then you have to display the number in
  • ---> word else if the number greater than 9 is
  • ---> entered you have to display Greater than 9


Coding


#include<iostream>
using namespace std;
int main()
{
    int n;
    cin>>n;
    if(n==1)
     {
         cout<<"one";
     }
     else if(n==2){
         cout<<"two";
     }
     else if(n==3){
         cout<<"three";
     }
     else if(n==4){
         cout<<"four";
     }
     else if(n==4){
         cout<<"four";
     }
     else if(n==5){
         cout<<"five";
     }
     else if(n==6){
         cout<<"six";
     }
     else if(n==7){
         cout<<"seven";
     }
     else if(n==8){
         cout<<"eight";
     }
     else if(n==9){
         cout<<"nine";
     }
     else {
     cout<<"Greater than 9";
     }

      return 0;
}


Explanation of solution


  • ---> first of all add the required header file then start of main function after 
  • that we declare integer type n and take this input from by using cin>>n.

  • ---> Then here we use the conditional statement in c++ and check if n==1
  • print 'one' and again check n==2 if yes then print 'two' like this we continue
  • till nine if n==9 then print 'nine'.

  •  ---> Then here we check if user enter the number greater than 9
  •   we have to print "Greater than 9" that we have written in the
  •   else condition that will print in last.

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